Liverpool and Egypt forward Mohamed Salah has won the 2018 Confederation of African Football Player of the Year – the second consecutive year at a ceremony in Senegal on Tuesday.
The Egyptian forward beat his Liverpool team-mate Sadio Mane of Senegal and Arsenal and Gabon striker Pierre-Emerick Aubameyang to the title.
“I have dreamt of winning this award since I was a child and now I have done so twice in a row,” Salah said after receiving the award.
He thanked his family,fans and teammates for their supports.
Salah scored 44 goals for Liverpool during the 2017-18 season, helping the Reds to the Champions League final before scoring twice for Egypt at the World Cup in Russia.
Houston Dash and South Africa forward Thembi Kgatlana was named Women’s Player of the Year.
No Nigerian male player is considered good enough to play for Africa, at the moment, as they missed out in Africa’s Best X1 unveiled at the annual CAF/Aiteo awards, held Tuesday night in Dakar, Senegal.
In the selection, African Footballer of the Year, Mohamed Salah of Egypt and Liverpool leads the attacking trio that consist Sadio Mane of Senegal and Liverpool and Pierre Emerick-Aubameyang of Arsenal and Gabon.
In the midfield are Riyad Mahrez of Algeria and Manchester City, Naby Keita of Guinea and Liverpool and Thomas Partey, of Ghana and Atletico Madrid.
Kalidou Koulibaly, who plays for Senegal and SSC Napoli, Eric Bailly, Ivory Coast and Manchester United, Medhi Benatia, of Morocco and Juventus and Serge Aurier of Ivory Coast and Tottenham Hotspur are in the defence.
To keep the goal is Denis Onyango, who plays for Uganda and South African Premier Soccer League club Mamelodi Sundowns.